[自動轉寄] (af2486) Re: 您好，想請問關於mathematica的問題

作者: chungyuandye (養花種魚數月亮賞星星)
標題: Re: 您好，想請問關於mathematica的問題
時間: Wed Dec 8 21:33:29 2010

Do那邊改成這樣看看可不可以

Quiet@FindRoot[f[(y (2 \[Pi]))/#, opt[#]] == 0, {y, 1.44677}] & /@
Range[1.54, 1.55, 0.005]

0.005是是公差，如果要做大量運算的話，自己找一下ParallelMap...

※ 引述《af2486 (我喜歡旅行)》之銘言：
: 您好，之前在暑假的時候曾經請教過mathematica的問題，非常感激
: 不過現在又有些問題想請教，不知是否有空撥冗幫我看一下呢?謝謝!
: 這是您之前幫我改過的程式碼：
: xiLimit = 15.;
: Hankel1[m_, x_] :=
: If[Abs[x] < xiLimit, BesselJ[m, x] + I BesselY[m, x],
: Sqrt[2/(Pi*x)] Exp[I*(x - m/2*Pi - Pi/4)]];
: BesselJp[m_, x_] :=
: If[Abs[x] < xiLimit,
: D[BesselJ[m, x1],
: x1] /. {x1 -> x}, -Sqrt[2/(Pi*x)] Sin[(x - m/2*Pi - Pi/4)]];
: BesselYp[m_, x_] :=
: If[Abs[x] < xiLimit, D[BesselY[m, x1], x1] /. {x1 -> x},
: Sqrt[2/(Pi*x)] Cos[(x - m/2*Pi - Pi/4)]];
: Hankel1p[m_, x_] :=
: If[Abs[x] < xiLimit, D[Hankel1[m, x1], x1] /. {x1 -> x},
: I*Sqrt[2/(Pi*x)] Exp[I*(x - m/2*Pi - Pi/4)]];
: kr[kz_, k_] := Sqrt[k^2 - kz^2];
: \[Alpha]r[kz_, k_] := Sqrt[kz^2 - k^2];
: f[kz_, opt_] := Module[{sub},
: k0 = \[Omega] Sqrt[\[Epsilon]0 \[Mu]0] /. opt;
: k1 = \[Omega] Sqrt[\[Epsilon]1 \[Mu]1] /. opt;
: k2 = \[Omega] Sqrt[\[Epsilon]2 \[Mu]2] /. opt;
: r0 = r0 /. opt;
: r1 = r1 /. opt;
: m = m /. opt;
: kr0 = kr[kz, k0];
: kr1 = kr[kz, k1];
: \[Alpha]r2 = \[Alpha]r[kz, k2];
: BJ00 = BesselJ[m, kr[kz, k0] r0];
: BJ10 = BesselJ[m, kr[kz, k1] r0];
: BJ11 = BesselJ[m, kr[kz, k1] r1];
: BY10 = BesselY[m, kr[kz, k1] r0];
: BY11 = BesselY[m, kr[kz, k1] r1];
: BJp00 = BesselJp[m, kr[kz, k0] r0];
: BJp10 = BesselJp[m, kr[kz, k1] r0];
: BJp11 = BesselJp[m, kr[kz, k1] r1];
: BYp10 = BesselYp[m, kr[kz, k1] r0];
: BYp11 = BesselYp[m, kr[kz, k1] r1];
: HA21 = Hankel1[m, I \[Alpha]r[kz, k2] r1];
: HAp21 = Hankel1p[m, I \[Alpha]r[kz, k2] r1];
: M = {{BJ00, 0, -BJ10, -BY10 , 0, 0, 0, 0},
: {0, BJ00, 0, 0, -BJ10, -BY10, 0, 0},
: {(\[Omega] \[Epsilon]0)/(kr0 r0) BJp00, (m kz)/(kr0^2 r0^2)
: BJ00, -((\[Omega] \[Epsilon]1)/(kr1 r0))
: BJp10, -((\[Omega] \[Epsilon]1)/(kr1 r0)) BYp10, -((m kz)/(
: kr1^2 r0^2)) BJ10, -((m kz)/(kr1^2 r0^2)) BY10, 0, 0},
: {(m kz)/(kr0^2 r0^2) BJ00, (\[Omega] \[Mu]0)/(kr0 r0)
: BJp00, -((m kz)/(kr1^2 r0^2)) BJ10, -((m kz)/(kr1^2 r0^2))
: BY10, -((\[Omega] \[Mu]1)/(kr1 r0))
: BJp10, -((\[Omega] \[Mu]1)/(kr1 r0)) BYp10, 0, 0 },
: {0, 0, BJ11, BY11 , 0, 0, -HA21, 0},
: {0, 0, 0, 0, BJ11, BY11, 0, -HA21},
: {0, 0, (\[Omega] \[Epsilon]1)/(kr1 r1)
: BJp11, (\[Omega] \[Epsilon]1)/(kr1 r1) BYp11, (m kz)/(
: kr1^2 r1^2) BJ11, (m kz)/(kr1^2 r1^2) BY11, (
: I \[Omega] \[Epsilon]2)/(\[Alpha]r2 r1) HAp21, (
: m kz)/(\[Alpha]r2^2 r1^2) HA21},
: {0, 0, (m kz)/(kr1^2 r1^2) BJ11, (m kz)/(kr1^2 r1^2)
: BY11, (\[Omega] \[Mu]1)/(kr1 r1) BJp11, (\[Omega] \[Mu]1)/(
: kr1 r1) BYp11, (m kz)/(\[Alpha]r2^2 r1^2) HA21, (
: I \[Omega] \[Mu]2)/(\[Alpha]r2 r1) HAp21}
: } /. opt;
: equ = Det[M];
: Return[equ];
: ]
: n0[lambda_] :=
: Sqrt[1 + (0.68671749*lambda^2)/(lambda^2 -
: 0.072675189^2) + (0.43481505*lambda^2)/(lambda^2 -
: 0.11514351^2) + (0.89656582*lambda^2)/(lambda^2 - 10.002398^2)];
: n1[lambda_] :=
: Sqrt[1 + (0.6961663*lambda^2)/(lambda^2 - 0.0684043^2) + (0.4079426*
: lambda^2)/(lambda^2 - 0.1162414^2) + (0.8974794*
: lambda^2)/(lambda^2 - 9.896161^2)];
: n2[lambda_] := 1.0;
: opt[lambda_] := {m -> 1, \[Omega] -> 2 Pi/lambda, r0 -> 4.1,
: r1 -> 62.5, \[Epsilon]0 -> n0[lambda]^2, \[Mu]0 ->
: 1., \[Epsilon]1 -> n1[lambda]^2, \[Mu]1 -> 1., \[Epsilon]2 ->
: n2[lambda]^2, \[Mu]2 -> 1., kz -> y};
: temp3 = NestList[{#[[1]] + 0.001, #[[3]], Re@y} /.
: FindRoot[
: f[y*(2 Pi/(#[[1]] + 0.001)), opt[#[[1]] + 0.001]] ==
: 0, {y, #[[3]]}] &, {0.999, 1.299, 1.45038}, 301][[2 ;; -1]]
: Export["temp3.csv", temp3[[All, 3]]]
: -------------------------------------------------------------
: 其中迴圈是用牛頓法在1~1.3之間每隔0.001找一次解
: 理想上想得到的解是約略成等差級數的解
: 可是現在遇到的問題是在某些點，找到的解會和上一點一樣，這並不是所想要的
: 請問這有可能程式哪邊出問題嗎?還是跟牛頓法有關呢?
: 不好意思麻煩了...謝謝!

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